Question

Calculate the work associated with the expansion of a gas from 122.0 L to 160.9 L at a constant pressure of 18.3 atm.

Answer 1

Given:

The initial volume of gas is V_i = 122 L

The final volume of gas is V_f = 160.9 L

The pressure of the gas is P = 18.3 atm

To find the work done.

Step-by-step explanation:

The work done in the expansion of gas will be

`\begin{gathered} W=-P(V_f-V_i) \\ =-18.3(160.9-122) \\ =-711.87\text{ L atm} \end{gathered}`

Conversion of L atm to J will be

`\begin{gathered} W=-711.87*101.33 \\ =\text{ 72133.79 J} \end{gathered}`