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Let n be a natural number such that the remainder of the division of 4294 by n is 10, and the remainder of the division of 3521 by n is 11. what is n?
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Let n be a natural number such that the remainder of the division of 4294 by n is 10, and the remainder of the division of 3521 by n is 11. what is n?

User Sandum
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4294 - 10 = 4284 and 3521 - 11 = 3510. The common factors of 4284 and 3510 are 18, 9, 6, 3, and 2. The problems that work are 18 because only with 18 do the remainders work out. Therefore n = 18
User Lfa
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