Answer:
9 tongue roller and smooth middle knuckles: 3 tongue roller and hairy middle knuckles : 3 Non-roller and smooth middle knuckle: 1 non-roller and hairy middle knuckle.
Step-by-step explanation:
Let's assume that allele for tongue roll is "R" and the allele for the non-roller phenotype is "r". Similarly, allele "S" determines smooth middle knuckles while its recessive counterpart "s" gives hairy middle knuckles.
The genotype of heterozygous parents would be "RrSs" and a cross between two "RrSs" genotypes would give progeny in the following phenotype ratio=
9 tongue roller and smooth middle knuckles: 3 tongue roller and hairy middle knuckles : 3 Non-roller and smooth middle knuckle: 1 non-roller and hairy middle knuckle.