The diagram illustrating the scenario is shown below
a) The inner box represents the initial size of the court that they made. x represents the extra distance that they could have added on either sides so that the area would be 4536 square feet. Recall, the area of a rectangle is length x width
Thus,
the new length = 60 + x + x = 60 + 2x
the new width = 30 + x + x = 30 + 2x
area = 4536
thus, the equation is
(60 + 2x)(30 + 2x) = 4536
b) We would expand the brackets. it becomes
60 * 30 + 60 * 2x + 2x * 30 + 2x * 2x = 4536
1800 + 120x + 60x + 4x^2 = 4536
4x^2 + 120x + 60x + 1800 = 4536
4x^2 + 180x + 1800 = 4536
Dividing both sides of the equation by 4, we have
x^2 + 45x + 450 = 1134
x^2 + 45x + 450 - 1134 = 0
x^2 + 45x - 684 = 0
We would solve the quadratic equation by factorising. We would find two terms such that their sum or difference is 45x and their product is - 684x^2. The terms are 57x and - 12x. thus, we have
x^2 + 57x - 12x - 684 = 0
By factorising, we have
x(x + 57) - 12(x + 57) = 0
(x - 12)(x + 57) = 0
x - 12 = 0 or x + 57 = 0
x = 12 or x = - 57
The value of x cannot be negative. Thus, x = 12
Therefore
The length and width of the court can be expanded by
12 * 2 = 24 feet
new length = 60 + 24 = 84 ft
new width = 30 + 24 = 54 ft
Checking, 84 x 54 = 4536 square feet