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a projectile is launched at an angle of 30 degrees and lands later at the same level. if it's initial speed is 50 m/s, solve for the time it is in the air, the maximum height it reaches, and the horizontal
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Mar 25, 2018
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a projectile is launched at an angle of 30 degrees and lands later at the same level. if it's initial speed is 50 m/s, solve for the time it is in the air, the maximum height it reaches, and the horizontal distance it travels.
Physics
middle-school
Huskerchad
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Maximum height
= (Usinα)^2/2g
(50*0.5)^2/20
25^2/20
625/20
=31.25metres
horizontal distance = Range= [U^2 * sin2α]/g
[50^2 * sin60]/10
2500 * 0.8660/10
2165/10=216.5metres
Praveen G
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Mar 30, 2018
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Praveen G
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