Question

One number is 5 less than 3 times a second number. Their sum is 43. Find the numbers

Answer 1

To find the numbers, we can set up a system of equations. Let 'x' represent the first number and 'y' represent the second number. The equations are: x = 3y - 5 and x + y = 43. By solving this system, we find that the numbers are 31 and 12.

Step-by-step explanation:

Let's represent the first number as 'x' and the second number as 'y'.

We are given that the first number is 5 less than 3 times the second number, so we can write the equation as:

x = 3y - 5

Additionally, we know that the sum of the two numbers is 43, so we can write another equation:

x + y = 43

Now we can solve the system of equations to find the values of x and y:

Substitute the value of x from the first equation into the second equation:

(3y - 5) + y = 43

Combine like terms:

4y - 5 = 43

Add 5 to both sides:

4y = 48

Divide both sides by 4:

y = 12

Now substitute the value of y back into the first equation:

x = 3(12) - 5

x = 36 - 5

x = 31

Therefore, the numbers are 31 and 12.

Answer 2

x= 3y-5

3y-5+3y= 43

6y= 43+5

y= 8

x= 3*8-5

x= 19

first number is 19

second is 8