Question

How to solve the second equation

Answer 1

`\bf \textit{ vertex of a vertical parabola, using coefficients}\\\\ \begin{array}{lccclll} y = &{{ -0.02}}x^2&{{ +1}}x&{{ +6}}\\ &\uparrow &\uparrow &\uparrow \\ &a&b&c \end{array}\qquad \left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right) \\\\\\ \left( -\cfrac{1^2}{2(-0.02)}~~,~~6-\cfrac{1^2}{4(-0.02)} \right) \\\\\\ (\stackrel{\textit{how far ahead it went}}{25}~,~\stackrel{\textit{how high it went}}{18(1)/(2)})`


`\bf \textit{ vertex of a vertical parabola, using coefficients}\\\\ \begin{array}{lccclll} y = &{{ -0.01}}x^2&{{ +0.7}}x&{{ +6}}\\ &\uparrow &\uparrow &\uparrow \\ &a&b&c \end{array}\qquad \left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right) \\\\\\ \left( -\cfrac{0.7^2}{2(-0.01)}~~,~~6-\cfrac{0.7^2}{4(-0.01)} \right) \\\\\\ (\stackrel{\textit{how far ahead it went}}{24(1)/(2)}~,~\stackrel{\textit{how high it went}}{18(1)/(2)})`