Register
If a buffer solution is 0.190 m in a weak acid (ka = 8.2 × 10-5) and 0.590 m in its conjugate base, what is the ph?\
129k views
1 vote
If a buffer solution is 0.190 m in a weak acid (ka = 8.2 × 10-5) and 0.590 m in its conjugate base, what is the ph?\

User Norbert Dopjera
by
7.6k points

1 Answer

6 votes
You use the Henderson - Hasselbalch equation pH = pKa + log ([salt]/[acid]) pKa = -log (8.2*10^-5) = 4.081 pH = 4.081 + (0.590/0.190) pH = 4.081 + log 3.105 pH = 4.081 + 0.49206 pH = 4.573
User Enyinnaya
by
9.0k points
← Prev Question Next Question →

Related questions

Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.5m questions

12.2m answers

Other Questions

Compare and contrast an electric generator and a battery??
How do you balance __H2SO4 + __B(OH)3 --> __B2(SO4)3 + __H2O
As an object’s temperature increases, the ____________________ at which it radiates energy increases.
Why is gold preferred as a superior metal over silver and bronze?
Which of the following statements does not describe a physical property of a piece of chalk A. Chalk is solid B.chalk can be broken into pieces C. Chalk is white D. Chalk will bubble in vinegar
Link Copied!