Solve for x 4x^2+28x+49=0

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asked Sep 2, 2018 188k views

1 Answer

Albert Still · Answer 1 · 2018-09-08T16:25:29+0000

4 x^2 + 28 x + 49 = 0
Divide both sides by 4:
x^2 + 7 x + 49/4 = 0
Write the left hand side as a square:
(x + 7/2)^2 = 0
Take the square root of both sides:
x + 7/2 = 0
Subtract 7/2 from both sides:
Answer: x = -7/2

Solve for x 4x^2+28x+49=0

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