Question

A sample of an ideal gas (3.00 l) in a closed container at 25^\circ c25∘c and 76.0 torr is heated to 300^\circ c300∘c. the pressure of the gas at this temperature is __________ torr.

Answer 1

Answer : The pressure of the gas at 300 °C is, 146 torr

Explanation :

Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.

`P\propto T`

or,

`(P_1)/(T_1)=(P_2)/(T_2)`

where,

`P_1` = initial pressure of gas = 76.0 torr

`P_2` = final pressure of gas = ?

`T_1` = initial temperature of gas =
`25^oC=273+25=298K`

`T_2` = final temperature of gas =
`300^oC=273+300=573K`

Now put all the given values in the above equation, we get:

`(76.0torr)/(298K)=(P_2)/(573K)`

`P_2=146torr`

Therefore, the pressure of the gas at 300 °C is, 146 torr