Question

The sum of two numbers is 50 . the difference is 28 find the 2 numbers using system of equations

Answer 1

let the two numbers be x and y
x+y=50----eqn1
x-y=28----eqn2
subtract eqn2 frm eqn1, you'll have:
2y=22
y=11
Then substitute y=1 in eqn1. you'll have:

x+11=50
x=50-11
x=39

∴x=39(the first number) and y=11(the second number)

Answer 2

Greetings!

Let x represent the first number
Let y represent the second number


`\left \{ {{x+y=50} \atop {x-y=28}} \right.`

Eliminate a variable:

`\frac{\left \{ {{x+y=50} \atop {x-y=28}} \right. }{2x=78}`

Solve for x:

`2x=78`

Divide both sides by 2.

`2x=78`


`(2x)/(2)=(78)/(2)`


`x=39`

Solve for the other variable:

`x+y=50`


`39+y=50`

Add -39 to both sides.

`39+y=50`


`(39+y)+(-39)=(50)+(-39)`


`y=11`

The Answer is:

`\left[\begin{array}{ccc}x=39, y=11\end{array}\right]`

One number is 39 and the other is 11.

Hope this helped!
-Benjamin