Question

A 25.0 ml sample of 0.105 M HCl is diluted to 31.5 ml. What is the final concentration of the HCl?

Answer 1

The final concentration of HCl is 0.0833 M

Step-by-step explanation

Given that;

The initial volume of HCl is 25.0mL

The final volume of HCl is 31.5mL

The initial concentration of HCl is 0.105 M

Apply the dilution formula to find the final concentration of HCl

`\text{ C1 V1 = C2 V2}`

Substitute the given data into the above formula

`\begin{gathered} \text{ 0.105 }*\text{ 25 }=\text{ 31.5 }*\text{ C2} \\ \text{ 2.625 = 31.5 C2} \\ \text{ Divide both sides by 31.5} \\ \text{ }(2.625)/(31.5)\text{ = C2} \\ C2\text{ = 0.0833 M} \end{gathered}`

Therefore, the final concentration of HCl is 0.0833 M