Question

Which trigonometric ratio would you use to solve for z when using the 28 degree angle?

Answer 1

sine because it uses opposite over hypotenuse

Answer 2

Sine

Explanation:

We are given that a triangle XMI in which

`MI=20 units`

`XI=z`

`\angle MXI=28^(\circ)`

We have to find which trigonometric ratio would use to solve for z.

We know that

`Sin\theta=(Perpendicular\;side)/(hypotenuse)`

`cosin\theta=(base)/(Hypotenuse)`

`tan\theta=(Perpendicular\;side)/(base)`

We have , Perpendicular side =MI=20 units

Hypotenuse,XI=z

Base=XM

`sin28^(\circ)=(20)/(z)`

`z=(20)/(sin28^(\circ))`

Hence, we would use sine to solve for z.