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1 vote
Amy, jean, keith, tom, susan, and dave have all been invited to a birthday party. they arrive randomly and each person arrives at a different time. in how many ways can they arrive? in how many ways can jean arrive first and keith last? find the probability that jean will arrive first and keith will arrive last

1 Answer

7 votes
I believe there are 36 different possibilities that Amy, Jean, Keith, Tom, Susan, and Dave can arrive.

User DiaWorD
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