1- -y^2+6y+x-9=0
2- 6y=x+27
we solve by substituting from the 2nd equation we get x=6y-27
substituting in equation 1
-y^2+6y+(6y-27)-9=0
-y^2+12y-36=0
y^2-12y+36=0
(y-6)(y-6)=0
y=6 since x=6y-27 x=36-27=9
the point of intersection of only soultion is (9,6)