Question

Write the equation of a line that is parallel to y=0.6x+3y, and that passes through the point(−3,−5)

Answer 1

It is y=0.6x-3.2

Explanation:

A line parallel to y = 0.6x + 3 will be of the form:

y = 0.6x + k

where k is a constant. It passes through (-3,-5)

That being so,

y = 0.6x + k

-5 = 0.6 * (-3) + k

-5 = -1.8 + k

k = -5 + 1

k= -3.2

Therefore the answer is y = 0.6x - 3.2.

Answer 2

y = -30/97x - 575/97

y=-0.30927835051x - 5.92783505155