Question

Use the three steps to solve the problem. the length of a rectangle is 2 inches less than 3 times the number of inches in its width. if the perimeter of the rectangle is 28 inches, what is the width and length of the rectangle? {width a0in., length a1in.}

Answer 1

p=28 in
l=3*w-2

p=2w+2l
p=2w+2*(3w-2)
p=2w+6w-2*2
p=8w-4
p=28 in
8w-4=28
8w=28+4
8w=32 in
w=32/8=4 in
l=3*4-2=12-2=10 in

Answer 2

Length of the rectangle is 10 inches and Width of the rectangle is 4 inches.

Explanation:

Given:

The length of a rectangle is 2 inches less than 3 times the number of inches in its width.

The perimeter of the rectangle is 28 inches.

To find: Width and Length of the Rectangle.

Step 1:

let be the width of the rectangle is x inches.

⇒ Length = 3x - 2

Step 2:

Perimeter of rectangle = 2 × ( Length + Width )

2 × ( 3x - 2 + x ) = 28

2 × ( 4x - 2 ) = 28

2 × 2 ( 2x - 1 ) = 28

4 × ( 2x - 1 ) = 28

2x - 1 = 28/4

2x - 1 = 7

2x = 7 + 1

2x = 8

x = 8/2

x = 4

Step 3:

Width of the rectangle = 4 inches

Length of the rectangle = 3 × 4 - 2 = 12 - 2 = 10 inches

Therefore, Length of the rectangle is 10 inches and Width of the rectangle is 4 inches.