Question

If an object is propelled upward from a height of s feet at an initial velocity of v feet per​ second, then its height h after t seconds is given by the equation hequals=minus−16t squaredt2plus+vtplus+​s, where h is in feet. if the object is propelled from a height of 88 feet with an initial velocity of 6464 feet per​ second, its height h is given by the equation hequals=minus−16t squaredt2plus+6464tplus+88. after how many seconds is the height 3636 ​feet?

Answer 1

im sorry i have no idea i think it would be half the time of 6464 ft per second