193k views
0 votes
Area swept out in the first revolution of spiral r=theta^2

User Doannx
by
7.4k points

1 Answer

5 votes
Answer: rc length=â«âšr2+(drdθ)2â‹…dθ for a equation r=θ2, drdθ=2θ â´ Arc length=â«âšÎ¸4+4θ2â‹…dθ by factoring out θ and rewriting a bit, =â«Î¸âšÎ¸2+4â‹…dθ=12â«(θ2+4)12â‹…2θdθ by General Power Rule, =12â‹…(θ2+4)3232+k=13(θ2+4)32+k Let's assume that 0≤θ≤2Ď€ Arc length=â«2Ď€0âšÎ¸4+4θ2â‹…dθ=92.9
User Saranya Krishnan
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories