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A single-turn wire loop 10 cm in diameter carries a 10 a current. it experiences a torque of 2.5×10−2 n⋅m when the normal to the loop plane makes a 33 ∘ angle with a uniform magnetic field.

1 Answer

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Answer: t = I B A sin teta 2.5 x 10^-2 = 10 B (pi 0.1^2 / 4) cos 23 B = 0.06 tesla
User Mmd Amin
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