Question

A certain ore yields an average of 59% iron. How much ore is needed to obtain 826 lb of iron?

Answer 1

First, convert 59% into decimal by dividing by 100%

`59\%/100\%=0.59`

Next, divide 826 lb by 0.59 to get the amount of ore needed

`826/0.59=1400`

Therefore, you need 1400 lb of ore to get 826 lb of iron.