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Ken is 6 feet tall and is walking away from a streetlight. The streetlight has its light bulb 14 feet above the ground, and Ken is walking at the rate of 1.7 feet per second. First, find a function, d(t), which gives the distance Ken is from the streetlight in terms of t (time in seconds). Second, find a function, , which gives the length of Ken's shadow in terms of d. Then find .

User Arkan
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1 Answer

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Distance = Y=1.7t
L = 6sin(tan^-1(d/8))
L = 6sin(tan^-1(1.7t/8))
User David Asaf
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