Question

The constraints of a problem are listed below. What are the vertices of the feasible region?

0, 0), (0, 3), (2, 3), (5, 0)
(0, 0), (0, 5), (2, 3), (5, 0)
(0, 0), (2, 3), (5, 0)
(0, 3), (0, 5), (2, 3)

Answer 1

A. (0, 0), (0, 3), (2, 3), (5, 0)

Explanation:

took the unit rev test, got it right.

Answer 2

The vertices are the intersections between the lines.

1) line x + y = 5 and y = 3:

y = 3 => x + 3 = 5 => x = 5 - 3 => x = 2

=> vertix = (2,3)

2) line x + y = 5 and y = 0

=> y = 0 => x + 0 = 5 => x = 5

=> vertix = (5,0)

3) line x + y = 5 and x = 0

=> 0 + y = 5 => y = 5

=> (0,5) ------> this is not a vertix because it is above the line y = 3

4) line y = 3 and x-axis

=> vertix = (0,3)

5) x-axis and y-axis => origin => vertix = (0,0)

So, there are four vertices: (0,0), (5,0), (2,3) and (0,3)

Answer: That is the first option:(0, 0), (0, 3), (2, 3), (5, 0)