Question

I have answered this question 8 times now and have yet to get the correct answer some one please help me. From algebra II

An object is launched at 19.6 meters per second from a 58.8 m tall platform. The equation for the object’s height h at time t seconds after launch is: h(t) = ‐4.9t2 + 19.6t + 58.8. After how many seconds does the object land?

Answer 1

when the object lands, the height is 0

0 = -4.9t^2 + 19.6t + 58.8
0 = -4.9(t^2 - 4t - 12)
0 = (t - 6)(t + 2)

t - 6 = 0
t = 6

t + 2 = 0
t = -2....cant be this one because it is negative

ur answer is 6 seconds