Question

An isosceles triangle has a base length 15. the length of each the other two equal sides is an integer. what is the shortest possible length of these other two sides

Answer 1

The lowest it can be is 8.
The sum of two sides of a triangle has to be greater than the remaining side, and since 8 + 8 = 16 which is greater than 15, this would be the answer. (It cannot be 7 since 7 + 7 equals 14)
I hope this helps.
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