Consider the parametric equation x=t+3,y=t2+4.x=t+3,y=t2+4. find a cartesian equation for this curve.

asked Apr 3, 2018 152k views

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$x=t+3\implies t=x-3$

$y=t^2+4\implies y=(x-3)^2+4=x^2-6x+13$

Joseph Young answered Apr 6, 2018