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If cos theta = 8/17 , find sin theta

User Aligator
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1 Answer

2 votes

Answer:

sin theta = 15/17

Explanation:

Let theta be A

sin^2 A = 1 - cos^2 A

sin^2 A = 1 - ( 8/17 )^2

sin^2 A = 1 - 64/289

sin^2 A = 289 - 64 /289

sin^2 A = 225 / 289

sin A = root 225/289

sin A = 15/17

so sin theta = 15/17

User Felesha
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