Question

Find the 33rd term of 7,10,13

Answer 1

The sequence given:

7, 10, 13, ...

This is an arithmetic sequence.

The first term (a1) is 7.

The common difference (d) between the terms is 10 - 7 =3, or 13 - 10 = 3.

To find the 33rd term of this sequence, we are going to use the nth term formula of an arithmetic sequence, shown below:

`a_n=a_1+(n-1)d`

Where

a_n is the nth term

a_1 is the first term

n is the number of the term

d is the common difference

Given,

a_1 = 7

d = 3

Let us find the 33rd term:

`\begin{gathered} a_n=a_1+(n-1)d \\ a_(33)=7+(33-1)3 \\ a_(33)=7+32(3) \\ a_(33)=7+96 \\ a_(33)=103 \end{gathered}`

Thus, the 33rd term of this arithmetic sequence is 103.

Answer

103