Question

Solve 2x^2 + 26 = 0 to identify the roots

Answer 1

2x^2=-26
x^2=-13
x=(+/-)sqrt(13)i

Answer 2

2nd and 3rd part of the problem:

The roots are imaginary because of the NEGATIVE RADICAND

There are two roots because of the NEED TO IDENTIFY + AND- ROOTS OF THE RADICAND

Explanation: