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What is the vertex of the graph of y = 3x2 + 2x + 1?

2 Answers

3 votes

Answer:

Its B on edge

Explanation:

User SamWhan
by
8.9k points
6 votes

Answer-

The vertex will be at
(-(1)/(3),(2)/(3))

Solution-

The parabolic equation given is,


y=3x^2+2x+1

Here,

a = 3, b = 2, c = 1

The equation of the axis of symmetry is,


x=-(b)/(2a)

Putting the values,


\Rightarrow x=-(2)/(2* 3)\\\\\Rightarrow x=-(1)/(3)

As we know, the axis of symmetry and the parabola meet only at one point and that is the vertex.

So, the vertex will be at
(-(b)/(2a),f(-(b)/(2a)))

Hence,


f(-(b)/(2a))=f(-(1)/(3))=3(-(1)/(3))^2+2(-(1)/(3))+1\\\\=3((1)/(9))-2((1)/(3))+1\\\\=(2)/(3)

What is the vertex of the graph of y = 3x2 + 2x + 1?-example-1
User Wirus
by
8.4k points

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