Question

What is the vertex of the graph of y = 3x2 + 2x + 1?

Answer 1

Its B on edge

Explanation:

Answer 2

The vertex will be at
`(-(1)/(3),(2)/(3))`

Solution-

The parabolic equation given is,

`y=3x^2+2x+1`

Here,

a = 3, b = 2, c = 1

The equation of the axis of symmetry is,

`x=-(b)/(2a)`

Putting the values,

`\Rightarrow x=-(2)/(2* 3)\\\\\Rightarrow x=-(1)/(3)`

As we know, the axis of symmetry and the parabola meet only at one point and that is the vertex.

So, the vertex will be at
`(-(b)/(2a),f(-(b)/(2a)))`

Hence,

`f(-(b)/(2a))=f(-(1)/(3))=3(-(1)/(3))^2+2(-(1)/(3))+1\\\\=3((1)/(9))-2((1)/(3))+1\\\\=(2)/(3)`