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What is the average rate of change of the function on the interval from x = 0 to x = 5?

f(x)=1/2(3)^x

User ThomasS
by
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2 Answers

3 votes
the average rate is 3^x/2
User Chris Bandy
by
7.4k points
3 votes

Answer:

Average rate of change = 24.2

Explanation:


f(x)=(1)/(2)3^x

Average rate of change formula is on interval a to b is


(f(b)-f(a))/(b-a)

Given interval is x=0 to x=5

a=0 and b=5

Average rate =
(f(5)-f(0))/(5-0)


f(0)=(1)/(2)3^0=\fracc{1}{2}=0.5


f(5)=(1)/(2)3^5=\frac{3^5}(2}=121.5

Average rate =
(f(5)-f(0))/(5-0)

Average rate =
(121.5-0.5)/(5)=24.2

Average rate of change = 24.2

User Boom
by
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