Question

I’m having trouble understanding how to solve number 1 under 5.3

Answer 1

Given

Solution

Formula

`\begin{gathered} \text{Area =}(1)/(2)*6*4*\sin 40^0 \\ \\ \text{Area =}(1)/(2)*24*\sin 40^0 \\ \\ \text{Area =}12*\sin 40^0 \\ \\ \text{Area =}7.71345 \end{gathered}`

The final answer

`\text{Area =7.7}1345unit^2`