Question

1²/ when x is 4.Y is inversely proportional to the cube of x. If Y = 8 when x = 2, then Y= 1O TrueFalse

Answer 1

Y is inversely proportional to the cube of x. This can be written as:

`Y=(k)/(x^3)`

Where k is the constant of proportionality.

We know Y = 8 when x = 2. Substituting:

`\begin{gathered} 8=(k)/(2^3) \\ \\ 8=(k)/(8) \\ \\ k=64 \end{gathered}`

Thus, the relationship is:

`Y=(64)/(x^3)`

When x = 4, calculate Y:

`Y=(64)/(4^3)=(64)/(64)=1`

When x = 4, Y = 1, thus the statement is false