Important: 35x2 12x − 36 is not an equation; to obtain an equation, you must set 35x2 12x − 36 = to 0:
35x^2 + 12x − 36 = 0. Also, "the square of x" must be represented by "x^2," and you must insert either the + or the - sign in front of the term 12x.
I am assuming that you meant 35x^2 + 12x − 36 = 0.
If that is indeed the case, then a = 35, b = 12 and c = -36
and the discriminant is b^2 - 4ac, or (12)^2 - 4(35)(-36) = 5184.
Since the discriminant is positive, this equation has 2 real, unequal solutions. They are
-12 plus or minus sqrt(5184)
x = -----------------------------------------
2(35)