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Find the area of the triangle with the given side lengths. Round to the nearest tenth.

Find the area of the triangle with the given side lengths. Round to the nearest tenth-example-1
User Stanislav Ivanov
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1 Answer

13 votes
13 votes

In order to solve this exercise, you can use the Heron's formula for the area of a triangle:


A=\sqrt[]{p(p-a)(p-b)(p-c)}

Where "a", "b" and "c" are the lengths of the sides of the triangle and "p" is half the perimeter.

The value of "p" can be found with this formula:


p=(a+b+c)/(2)

Where "a", "b" and "c" are the lengths of the sides of the triangle.

In this case, you can set up that:


\begin{gathered} a=30\operatorname{cm} \\ b=35\operatorname{cm} \\ c=47\operatorname{cm} \end{gathered}

Then, you can find "p":


\begin{gathered} p=\frac{30\operatorname{cm}+35\operatorname{cm}+47\operatorname{cm}}{2} \\ \\ p=56\operatorname{cm} \end{gathered}

Then, substituting values into the Heron's formula and evaluating, you get:


\begin{gathered} A=\sqrt[]{(56cm)(56cm-30\operatorname{cm})(56cm-35\operatorname{cm})(56cm-47\operatorname{cm})} \\ A=\sqrt[]{275,154} \\ A\approx524.6\operatorname{cm}^2 \end{gathered}

The answer is:


A\approx524.6\operatorname{cm}

User Markc
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