Question

Unless specifically stated otherwise, you may assume the speed of sound for all the scenarios below is 350 m/s.3.A bird watcher is recording bird songs (making him more of a bird listener than a bird watcher). He records the song of a south African swallow at 560 Hz as it was travelling at 12 m/s towards him. What is the actual frequency of a south African swallow’s song?

Answer 1

Given

The observed frequency is f'=560 Hz

The speed of the source, v'=12 m/s

Speed of sound, v=350 m/s

To find

The actual frequency

Step-by-step explanation

When the source is moving towards the observer

`\begin{gathered} f^(\prime)=f^((v)/(v-v^(\prime))) \\ \Rightarrow560=f((350)/(350-12)) \\ \Rightarrow f=540.8\text{ Hz} \end{gathered}`

Conclusion

The actual frequency is 540.8 Hz