The polynomial is not factorable, so use the quadratic formula.
y^2 + 8y + 19 = 0
x = (-b +- sqrt(b^2 - 4ac))/(2a)
x = (-8 +- sqrt(8^2 - 4(1)(19))/(2 * 1)
x = (-8 +- sqrt(64 - 76))/2
x = (-8 +- sqrt(-12))/2
If you have not learned imaginary/complex numbers, then the answer is "No solution" since there is no real number solution.
If you have learned imaginary/complex numbers, then we'll continue.
x = (-8 +- 2i sqrt(3))/2
x = -4 +- i sqrt(3)