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I’m having trouble I need this answered, it is apart of my ACT prep guide

I’m having trouble I need this answered, it is apart of my ACT prep guide-example-1
User Smokku
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1 Answer

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14 votes

Question:

Solution:

According to the data of the problem, the series is given by the following expression:


\sum ^(\infty)_(n\mathop=1)(n)/(3^n)=(1)/(3^1)+(2)/(3^2)+(3)/(3^3)+\cdots

now, remember the ratio test:

Suppose we have the series


\sum ^{}_{}a_n

Define,


L\text{ =}\lim _(n\to\infty)|(a_(n+1))/(a_n)|

Then,

if L<1, the series is absolutely convergent (and hence convergent).

if

L>1, the series is divergent.

if

L=1 the series may be divergent, conditionally convergent, or absolutely convergent.

Applying this definition to the given series, we obtain:


L\text{ =}\lim _(n\to\infty)|\frac{(n+1)3^n_{}}{n3^(n+1)_{}}|=(1)/(3)<1

then, the given series is absolutely convergent (and hence convergent). So that, we can conclude that the correct answer is:

I’m having trouble I need this answered, it is apart of my ACT prep guide-example-1
I’m having trouble I need this answered, it is apart of my ACT prep guide-example-2
User Tuyen Cao
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