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Does anyone know how to do this?
asked
Jul 2, 2018
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Does anyone know how to do this?
Mathematics
high-school
Ajo
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It is factorable if you can solve it when it equals 0.
There are many ways to do this.
X^2+bx+12=0
This equation gives a good answer if
Joekarl
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Jul 5, 2018
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You're looking for values to factor this equation into (x+p)(x+q)
such that pq=12 and p+q=b
Assuming we're looking for simple values, you can start by factorizing 12:
12 = 3*4 = 2*6 = 12*1 = -3*-4 = -2*-6 = -12*-1
For 3 and 4, b would be 7
2 and 6 => b=8
12 and 1 => b=13
and for the negatives
b can be -7, -8 or -13
So the total set is -13, -8, -7, 7, 8, 13
Jason Wiener
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Jul 9, 2018
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Jason Wiener
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