Question

Which term of the arithmetic sequence 1 , 6 , 11 , 16 , ... 1,6,11,16,... is 136?

Answer 1

the nth term = the first term +(n-1)d, d is the difference between two adjacent terms, in this case, d=5
136=1+5(n-1)
136=5n-4
5n=140
n=28

so the 28th term is 136