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Solve the system of equations by graphing
\left \{ {{y=- (3)/(2)x+2 } \atop {y=3x-7}} \right. *Show all work

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1) Graph of y = - (3/2)x + 2

That is a straightline with slope -3/2 and y-intercept 2

If you do not know how to graph it, you can make a table like this:

x y = (-3/2)x + 2

-1 3/2 + 2 = 7/2

0 0 + 2 = 2

2 - 3 + 2 = -1

4 - 6 + 2 = - 4

2) Graph of y = 3x - 7

That is a straight line with slope 3 and y intercept -7

If you do not know how to graph it you can make a table like this:

x y = 3x - 7

-1 - 3 - 7 = - 10

0 0 - 7 = - 7

1 3 - 7 = - 4

2 6 - 7 = - 1

3 9 - 7 = 2

3) When you draw the two lines you will see that the intersect at x = 2, with the correspondant y = - 1.

That point of intercection is the solutions of the system (2, -1)
User David Raznick
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