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What is the vertex of the quadratic function f(x)=(x-8)(x-2)?

User Lorilee
by
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2 Answers

3 votes

Answer: 5, -9

Explanation:

trust

User Zef Hemel
by
7.9k points
5 votes
change the function into vertex form:
f(x)=x²-10x+16
make a square by (adding half of -10)², which is 25, then subtract it:
f(x)=x²-10x+25-25+16
f(x)=(x-5)²-9
so the vertex is at (5,-9)

another way to do it:
f(x)=x²-10x+16
the vertex is when x=-
(b)/(2a), b=-10, a=1 in this case.
x=-(-10/2*1)=5
plug x=5 into the quadratic function, you get f(x)=-9
User Sajad Mirzaei
by
7.7k points

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