Question

How many moles of magnesium nitrate are produced from 143.2 grams of nitric acid, HNO3?

2HNO3 + Mg(OH)2 = Mg(NO3)2 + 2H2O

Answer 1

1.14 mol

Step-by-step explanation:

Given data:

Mass of HNO₃ react = 143.2 g

Moles of Mg(NO₃)₂ produced = ?

Solution:

Chemical equation:

2HNO₃ + Mg(OH)₂ → Mg(NO₃)₂ + 2H₂O

Number of moles of HNO₃:

Number of moles = mass/molar mass

Number of moles = 143.2 g/ 63.01 g/mol

Number of moles = 2.273 mol

Now we will compare the moles of HNO₃ and Mg(NO₃)₂

HNO₃ : Mg(NO₃)₂

2 : 1

2.273 : 1/2×2.273 = 1.14 mol