P(being delayed on M1) = 0.5 →P(NOT being delayed on M1) = 1-0.5 = 0.5
P(being delayed on M42)=0.75→P(NOT being delayed on M42) = 1-0.75= 0.25
P(NOT being delayed on M1) AND P(NOT being delayed on M42) = 0.5x0.25
→ 0.125 = 1/8
So, the chances he will not be delayed on his journey is 1/8