Question

Write the standard form of the line that contains a slope of -3/8 and passes through the point (5, -4). Include your work in your final answer. Type your answer in the box provided or use the upload option to submit your solution.

Answer 1

Answer and work shown above

Answer 2

Answer:
`3x+8y+17=0`

Explanation:

We know that the equation of a line passing through a point (a,b) ans has slope 'm' is given by :-

`(y-b)=m(x-b)`

Given : Slope :
`m=(-3)/(8)`

Point = (5, -4)

Then, the equation of a line passing through a point (5, -4) ans has slope
`(-3)/(8)` is given by :-

`(y-(-4))=(-3)/(8)(x-5)\\\\\Rightarrow\ 8(y+4)=-3(x-5)\\\\\Rightarrow\ 8y+32=-3x+15\\\\\Rightarrow\ 3x+8y+32-15\\\\\Rightarrow\ 3x+8y+17=0\ \ [\text{In standard form}]`

Therefore, the standard form of the line that contains a slope of
`(-3)/(8)` and passes through the point (5, -4):

`3x+8y+17=0`