Question

Find the complete factorization of the expression.

10xyz + 24xy + 6xz
A) xyz(5 + 12 + 3)
B) 2x(5zy + 12y + 3z)
C) x(10zy + 24y + 6z)
D) 2(5xzy + 12xy + 3xz)

Answer 1

it well be B.) they all have a factor of 2

Answer 2

B) 2x(5zy + 12y + 3z)

Explanation:

First, all coefficient for each term are a pair number, therefor 2 is common factor for all these

`10xyz + 24xy + 6xz=>2(5zxy + 12xy + 3xz )`

then, the variable X is present for each term of the funtion
`(5zxy + 12xy + 3xz)`, so, the variable X is a common factor to.

`2(5zxy + 12xy + 3xz )=> 2x(5zy + 12y + 3z )`