Question

Denise is conducting a physics experiment to measure the acceleration of a falling object when it slows down and comes to a stop. She drops a wooden block with a mass od 0.5 kilograms on a sensor on the floor. The sensor measures the force of the impact as 4.9 newtons. Whats the acceleration of the wooden block wgen it hits the sensor

Answer 1

we need a and we have m and F . Now a = f÷m so therefore a = 4,9 ÷ 0,5 which is 0,98 metres per cubic second

Answer 2

`a = 9.8 m/s^2`

Step-by-step explanation:

As we know that here given parameters are

`mass = 0.5 kg`

also we know that force of impact on the floor is given as

`F = 4.9 N`

now we know by the Newton's 2nd law says that the net force on an object is product of mass and its acceleration

it is given by

`F = ma`

now we have

`a = (F)/(m)`

`a = (4.9)/(0.5)`

`a = 9.8 m/s^2`