Question

Consider the chemical equilibrium of the following reaction CH3COOH    CH3COO– (aq) + H+(aq) What will happen to the chemical equilibrium of the solution if CH3COONa is added? The equilibrium will shifts to the right. The equilibrium will shifts to the left. The equilibrium will be unaffected. The equilibrium will be lost.

Answer 1

C

Step-by-step explanation:

Answer 2

Answer: The equilibrium will shifts to the left.

Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

`CH_3COOH\rightleftharpoons CH_3COO^-+H^+`

Thus if
`CH_3COONa` is added it will dissociate to give
`CH_3COO^-` and
`Na^+`

`CH_3COONa\rightarrow CH_3COO^-+Na^+`

Thus as the concentration of
`CH_3COO^-` increases, the equilibrium will shift in a direction where concentration of
`CH_3COO_-` decrease i.e. the dissociation of
`CH_3COOH` will be further depressed i.e the equilibrium will shift to the left.