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Solve the exponential equation. express the solution set in terms of natural logarithms 5^×+7=2

User MPaulo
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5^(x+7)=2
the known number is in the exponent, so use log to solve
Log both sides: log5^(x+7)=log2
(x+7)log5=log2
x+7=log2/log5
x=log2/log5 -7
the result needs to be logarithms, so the above is your final answer
User Delbis
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