Question

Solve for x:

4/x-3 + 2/x^2-9 = 1/x+3

a. -17/3

b.13/3

c.19/3

d.-5

Answer 1

`\frac4{x-3}+\frac2{x^2-9}=\frac1{x+3}`


`(4(x+3))/((x+3)(x-3))+\frac2{x^2-9}=(x-3)/((x+3)(x-3))`


`(4x+12)/(x^2-9)+\frac2{x^2-9}=(x-3)/(x^2-9)`


`(4x+12+2-(x-3))/(x^2-9)=0`


`(3x+17)/(x^2-9)=0`


`3x+17=0\implies x=-\frac{17}3`